abbym1420
abbym1420 abbym1420
  • 06-11-2019
  • Mathematics
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Use half angle to find the exact value of tan 15º

Respuesta :

prozehus
prozehus prozehus
  • 08-11-2019

Answer:

0.2679

Step-by-step explanation:

Knowing that tg 45⁰ = 1, tg 30⁰= [tex]1/\sqrt{3}[/tex], and tg (a-b) = [tex]\frac{tg a - tg b}{1+tg a. tg b}[/tex] we have: tg 15⁰ = tg (45⁰-30⁰) = (tg 45⁰-tg 30⁰) / (1+tg 45⁰. tg 30⁰) = [tex]\frac{1-1/\sqrt{3} }{1+1/\sqrt{3} } = \frac{\frac{\sqrt{3}-1 }{\sqrt{3} } }{\frac{\sqrt{3}+1 }{\sqrt{3} } } = \frac{\sqrt{3}-1 }{\sqrt{3}+1 }[/tex] = 0.73205/2.73205 = 0.26794

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