TayRexxle
TayRexxle TayRexxle
  • 08-06-2016
  • Mathematics
contestada

A=1/3 (a+b+c)<br /> Solve for C<br /> Will give thanks to anyone who answers

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TSO
TSO TSO
  • 08-06-2016
[tex]a = \frac{1}{3} (a+b+c)\\\\3a = a + b + c\\\\ 3a - a = a - a + b + c\\\\2a = b + c\\\\2a - b = b - b + c\\\\2a-b = c\\\\\\ \boxed{\bf{c = 2a - b}}[/tex]
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