Answer:
Q = -4702.5 J
Explanation:
Given data:
Mass of water = 25 g
Initial temperature = 75°C
Final temperature = 30°C
Heat released = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = T2 - T1
ΔT = 30°C - 75°C
ΔT = -45°C
Q = m.c. ΔT
Q = 25 g× 4.18 J/g.°C × -45 °C
Q = -4702.5 J
