Answer:
Induced emf will be 0.468 volt
Explanation:
We have given diameter of wire d = 15.3 cm
So radius [tex]r=\frac{d}{2}=\frac{15.3}{2}=7.65cm[/tex]
So area [tex]A=\pi r^2=3.14\times (7.65)^2=183.76\times 10^{-4}m^2[/tex]
Change in magnetic field dB = 0.26 - 0.77 = -0.51 T
Time for change in magnetic field dt = 0.26 sec
We know that emf is given by [tex]e=\frac{-d\Phi }{dt}=-A\frac{dB}{dt}=-183.76\times 10^{-4}\times \frac{-0.51}{0.2}=0.0468volt[/tex]
