Answer:
6.0 moles of H₂S are produced.
Explanation:
Let's consider the following balanced equation.
2 CH₄ + S₈ → 2 CS₂ + 4 H₂S
The molar ratio of S₈ to H₂S is 1 mol S₈: 4 mol H₂S. The moles of H₂S produced when 1.5 mol of S₈ react are:
1.5 mol S₈ × (4 mol H₂S/ 1 mol S₈) = 6.0 mol H₂S
6.0 moles of H₂S are produced, when 1.5 mol of S₈ react.
