For this case we have the following inequality:
[tex]1 <3x-2 <10[/tex]
Adding 2 on all three sides and inequality we have:
[tex]1 + 2 <3x-2 + 2 <10 + 2\\3 <3x <12[/tex]
We divide the three sides of inequality by 3:
[tex]\frac {3} {3} <\frac {3x} {3} <\frac {12} {3}\\1 <x <4[/tex]
Thus, the solution is given by the values of "x" between 1 and 4 without including 1 and 4. That is:
[tex](1,4)[/tex]
Answer:
The solution is given by x: (1,4)
