Answer:
3
Step-by-step explanation:
Given the geometric sequence
[tex]\dfrac{4}{3},\ 4,\ 12,\ 36,\ ...[/tex]
In this sequence,
[tex]b_1=\dfrac{4}{3}\\ \\b_2=4\\ \\b_3=12\\ \\b_4=36\\ \\...[/tex]
The common ratio r is equal to
[tex]r=\dfrac{b_2}{b_1}\\ \\r=\dfrac{b_3}{b_2}\\ \\r=\dfrac{b_4}{b_3}\\ \\...[/tex]
Since
[tex]\dfrac{b_2}{b_1}=\dfrac{4}{\frac{4}{3}}=3\\ \\\dfrac{b_3}{b_2}=\dfrac{12}{4}=3\\ \\\dfrac{b_4}{b_3}=\dfrac{36}{12}=3\\ \\...[/tex]
you have that the common ratio is r = 3.
