Answer:
The value of det(adj(A)) is 16.
Step-by-step explanation:
It is given that A is a 3x3 matrix with det(A) = 4.
We need to find the value of det(adj(A)).
We have a formula
[tex]det(adj(A))=(det(A))^{n-1}[/tex]
where, n is order of the square matrix.
Substitute det(A) = 4 and n=3 in the above formula.
[tex]det(adj(A))=(4)^{3-1}[/tex]
[tex]det(adj(A))=(4)^{2}[/tex]
[tex]det(adj(A))=16[/tex]
Therefore, the value of det(adj(A)) is 16.
