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09-01-2020
Chemistry

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What is the mass of 1.63 moles and f ammonium phosphorus (NH4)3PO4

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gbustamantegarcia054 gbustamantegarcia054

09-01-2020

Answer:

mass (NH4)3PO4 = 243.011 g

Explanation:

mass (NH4)3PO4 = ?

∴ moles (NH4)3PO4 = 1.63 moles

∴ molecular weight (Mw) = 149.0867 g/mol

mass = (mol)×(Mw)

⇒ mass (NH4)3PO4 = ( 1.63 mol (NH4)3PO4 )×( 149.0867 g/mol )

⇒ mass (NH4)3PO4 = 243.011 g

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