Answer:
10 M
Explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = ? M
V₁ = 8.0 mL
M₂ = 2.0 M
V₂ = 40 mL
Using the above formula , the molarity of acid , can be calculated as ,
M₁V₁ = M₂V₂
M₁ * 8.0mL = 2.0 M * 40mL
M₁ = 10 M
Hence, the molarity of the acid = 10 M
