Soren is flying a kite on the beach. The string forms a 45 degree angle with the ground. If he has let out 16
meters of line, how high above the ground is the kite? Round your answer to the nearest tenth of a meter.

We can solve this with the trigonometric function sine if we imagine there is a right triangle formed, where the hypotenuse is the length of the kite string and the triangle's opposite side is the height [tex]H[/tex] of the kite above ground.

Then:

[tex]cos(45\°)=\frac{opposite-side}{hypotenuse}=\frac{H}{16 m}[/tex]

Isolating [tex]H[/tex]:

[tex]H=cos(45\°) (16 m)[/tex]

Finally:

[tex]H=11.31 m \approx 11 m[/tex]

Soren is flying a kite on the beach. The string forms a 45 degree angle with the ground. If he has let out 16 meters of line, how high above the ground is the kite? Round your answer to the nearest tenth of a meter.

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Soren is flying a kite on the beach. The string forms a 45 degree angle with the ground. If he has let out 16
meters of line, how high above the ground is the kite? Round your answer to the nearest tenth of a meter.