Answer: d. (17, 20)
Step-by-step explanation:
We have the following system of equations:
[tex]x-3y=8[/tex] (1)
[tex]5x-4y=5[/tex] (2)
Isolating [tex]x[/tex] from (1):
[tex]x=\frac{8+3y}{4}[/tex] (3)
Substituting (3) in (2):
[tex]5(\frac{8+3y}{4})-4y=5[/tex] (4)
Isolating [tex]y[/tex]:
[tex]\frac{40}{4}+\frac{15 y}{4}-4y=5[/tex] (5)
[tex]10-5=4y-\frac{15 y}{4}[/tex] (6)
[tex]y=20[/tex] (7)
Substituting (7) in (1):
[tex]x-3(20)=8[/tex] (8)
Isolating [tex]x[/tex]:
[tex]x=17[/tex] (9)
Hence, the correct option is d. (17, 20)
