Answer:
1)m<DCH =89
2)m<BCD=103
Step-by-step explanation:
1) We have that:
m<EFB=91 degree.
We want to find m<DCH.
By same side interior angle property:
m<DCH +m<EFB=180
m<DCH +91=180
m<DCH=180-91
m<DCH =89
2) Given that: m<HFG=103, we seek to find m<BCD.
By the alternate exterior angle property:
m<HFG=m<BCD
Therefore
m<BCD=103
