Answer:
[tex]\huge\boxed{n=\log_35}[/tex]
Step-by-step explanation:
[tex]3^n=5\Rightarrow\log_33^n=\log_35\qquad\text{use}\ \log_ab^n=n\log_ab\\\\n\log_33=\log_35\qquad\text{use}\ \log_aa=1\\\\\boxed{n=\log_35}[/tex]
