iayannamitchell
iayannamitchell iayannamitchell
  • 06-03-2020
  • Mathematics
contestada

What is the factorization of 36b^4 – 64?

Respuesta :

jimrgrant1 jimrgrant1
  • 06-03-2020

Answer:

4(3b² + 4)(3b² - 4)

Step-by-step explanation:

Given

36[tex]b^{4}[/tex] - 64 ← factor out 4 from each term

= 4(9[tex]b^{4}[/tex] - 16) ← factor as a difference of squares

a² - b² = (a + b)(a - b), thus

9[tex]b^{4}[/tex] - 16

= (3b²)² - 4²

= (3b² + 4)(3b² - 4)

Hence

36[tex]b^{4}[/tex] - 64

= 4(3b² + 4)(3b² - 4) ← in factored form

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