Answer:
x = [tex]\frac{1}{4}[/tex], y = 0
Step-by-step explanation:
Given the 2 equations
40x + 3y = 10 → (1)
20x - 7y = 5 → (2)
Multiplying (2) by - 2 and adding to (1) will eliminate the x- term
- 40x + 14y = - 10 → (3)
Add (1) and (3) term by term, that is
17y = 0 ⇒ y = 0
Substitute y = 0 into either of the 2 equations and solve for x
Substituting y = 0 in (1)
40x + 3(0) = 10, that is
40x = 10 ( divide both sides by 40 )
x = [tex]\frac{10}{40}[/tex] = [tex]\frac{1}{4}[/tex]
