Answer:
[tex]P(A \: and \: B) = 0.048[/tex]
Step-by-step explanation:
Recall that the probability of event A , given that event B has occurred is given as:
[tex]P(A|B)=\frac{P(A\cap B)}{P(B)}[/tex]
Since P(A|B) = 0.08 and P(A) = 0.40 are not the the two events are not independent.
We substitute the probabilities to get:
[tex]0.08=\frac{P(A\cap B)}{0.60}[/tex]
[tex]P(A\cap B) = 0.08 \times 0.6 = 0.048[/tex]
Therefore
[tex]P(A \: and \: B) = 0.048[/tex]
