taylornspencer12 taylornspencer12
  • 07-07-2016
  • Mathematics
contestada

Find S15 for the geometric series 72 + 12 + 2 + 1/3 +

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miguelt679
miguelt679 miguelt679
  • 07-07-2016
finish the equation. please and thank you

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caylus
caylus caylus
  • 07-07-2016
Hello,

[tex]u_{1}=72\\ u_{2}=\dfrac{72}{6}\\ u_{3}=\dfrac{72}{6^{2}}\\ u_{15}=\dfrac{72}{6^{14}}\\ s=72*(1+\dfrac{1}{6^{1}}+\dfrac{1}{6^{2}}+\dfrac{1}{6^{3}}++...+\dfrac{1}{6^{14}})\\ =72*(\dfrac{\frac{1}{6^{15}}-1}{\frac{1}{6}-1}})\\ =72*(\dfrac{470184984576-1}{78364164095*5})\\ =86,400... [/tex]
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