Neymar0421
Neymar0421 Neymar0421
  • 06-04-2020
  • Mathematics
contestada

Givin sin0= 12/13, find sec(0)

A. Sec(0)= 13/12

B. Sec(0)= 5/13

C. Sec(0)= 5/12

D. Sec(0)= 13/5

Respuesta :

elliottou
elliottou elliottou
  • 06-04-2020

Answer:

D. sec(a) = 13/5

Step-by-step explanation:

if sin(a) = 12/13, then cos (a) = 5/13, because of 5-12-13 triangles

sec(a) = 1/cos(a)

1/(5/13) = 13/5

sec(a) = 13/5

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