2023elizettesmi 2023elizettesmi
  • 06-04-2020
  • Mathematics
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Help i'll make you the brainliest
Solve S = 2ab + 2bc + 2ac for b
A) S - 4a c
B) S 2(a + c)
C) S a + b + c
D) S - 2ac 2a + 2c

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Аноним Аноним
  • 06-04-2020

Answer:

D) b = [tex]\frac{S-2ac}{2a + 2c}[/tex]

Step-by-step explanation:

First, move all the terms that do not include b to the left side with S:

S = 2ab + 2bc + 2ac

S - 2ac = 2ab + 2bc

Now, factor out 2b from the right side:

S - 2ac = 2b(a + c)

Divide both sides by 2(a + c):

b = [tex]\frac{S-2ac}{2(a + c)}[/tex]

Finally, multiply out the denominator:

b = [tex]\frac{S-2ac}{2a + 2c}[/tex]

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