The deBroglie wavelength of a proton with a velocity of 2.5e6 is λ=1.654*10^24 m2 kg
Explanation:
We have the formula,
λ = h/mv
λ = h/p (p=mv) assume mass be 1
λ = 6.62607004 × 10-34 m2 kg / s
/2.5*1.602176634*10^−19*10^6
λ = 6.62607004 × 10-34 m2 kg / s / 4.005425
*10^-13
λ=1.654*10^24 m2 kg
The deBroglie wavelength of a proton with a velocity of 2.5e6 is λ=1.654*10^24 m2 kg
