Answer:
emf=-0.035V
Explanation:
this problem can be solved with the Lenz's law:
[tex]emf=-\frac{\Delta \Phi_{B}}{\Delta t}[/tex]
where PhiB is the magnetic flux. In this case we have
[tex]\Delta \Phi_{B}=B(A_1-A_2)[/tex]
due to the magnetic field is constant. A is the area of the circular loop. Hence
[tex]\Delta \Phi_{B}=(5*10^{-3}T)(\pi(3m)^2-\pi(1.5m)^2)=0.106Tm^2[/tex]
Finally
[tex]emf=-\frac{0.106Tm^2}{3s}=-0.035V[/tex]
HOPE THIS HELPS!!
