Respuesta :

elliottou

Answer:

4

Step-by-step explanation:

the standard equation of a circle will be given in the form of

[tex](x-x_{1} )^2+(y-y_{1} )^2 = r^2[/tex], where r is the radius and (x1, y1) is the center point of the circle

in this situations r^2 = 16

r = +4 or -4, but since length cannot be negative, r = 4

ulili

Answer:

4

Step-by-step explanation:

from the circle equation ( x - h )^2 + ( y - k )^2 = r^2, 16 is the radius squared, so x^2=16

x= 4 x=-4

we reject -4, bc it's negative, and a radius cannot be negative,

r=4

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