Given:
ΔABC is an equilateral triangle.
AB = 7.5x, BC = 6x + 3 and CA = 10x - 5
To find:
The value of x.
Solution:
In equilateral triangle, all sides are equal.
AB = BC = CA
[tex]7.5x=6x + 3 = 10x - 5[/tex]
Take any two sides only:
AB = BC
[tex]7.5 x=6 x+3[/tex]
Subtract 6x from both sides.
[tex]7.5 x-6 x=6x+3-6x[/tex]
[tex]1.5 x=3[/tex]
Divide by 1.5 on both sides.
[tex]$\frac{1.5 x}{1.5}=\frac{3}{1.5}[/tex]
[tex]x=2[/tex]
The value of x is 2.
