Answer:
x = 5
Step-by-step explanation:
because the log is base 2 you can remove the log by raing 2 to the power of each side:
[tex]2^{log2 (3x-7)} = 2^{3}[/tex]
the 2 and log2 cancel leaving:
[tex]3x-7 = 2^{3}[/tex]
this means we can now solve through simple algebra:
[tex]3x-7 = 8\\3x = 8 + 7\\3x = 15\\3x/3 =15/3\\x = 5[/tex]
