erickroberto5891 erickroberto5891
  • 07-05-2020
  • Mathematics
contestada

Write a polynomial function that meets the given conditions. Answers may vary. Degree 2 polynomial with zeros of 2√ 13 and -2√13

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joaobezerra joaobezerra
  • 11-05-2020

Answer:

The polynomial function is [tex]x^{2} - 52[/tex]

Step-by-step explanation:

A polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = (x - x_{1})*(x - x_{2})[/tex].

In this problem:

The roots are [tex]x_{1} = 2\sqrt{13}[/tex] and [tex]x_{2} = -2\sqrt{13}[/tex]

Then

[tex](x - 2\sqrt{13}) \times (x - (-2\sqrt{13})) = (x - 2\sqrt{13}) \times (x + 2\sqrt{13}) = x^{2} - 2x\sqrt{13} + 2x\sqrt{13} -(2\sqrt{13})^{2} = x^{2} - 52[/tex]

The polynomial function is [tex]x^{2} - 52[/tex]

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