rothrockjayden rothrockjayden
  • 07-05-2020
  • Chemistry
contestada

What mass of NaOH must be used to prepare 2.5 L of a 0.010 M solution

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xero099
xero099 xero099
  • 13-05-2020

Answer:

[tex]m = 1\,g[/tex]

Explanation:

The molarity is the ratio of the amount of moles solvent to volume of the solute.

[tex]0.010\,M = \frac{0.010\,moles\,NaOH}{1\,L}[/tex]

The quantity of solute is determined by simple rule of three:

[tex]n = \left(\frac{2.5\,L}{1\,L} \right)\cdot (0.010\,mole)[/tex]

[tex]n = 0.025\,moles[/tex]

The molecular weight of NaOH is [tex]39.997\,\frac{g}{mole}[/tex], the mass of solute is:

[tex]m = 1\,g[/tex]

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