e3kardatzke
e3kardatzke e3kardatzke
  • 08-05-2020
  • Mathematics
contestada

these are all my points I'm desperate please help I've posted this 4 other times

these are all my points Im desperate please help Ive posted this 4 other times class=

Respuesta :

wegnerkolmp2741o
wegnerkolmp2741o wegnerkolmp2741o
  • 08-05-2020

Answer:

y = (x+3)^2 -1

Step-by-step explanation:

The vertex form of the equation is

y = a(x-h)^2 +k  where (h,k) is the vertex

The vertex is (-3,-1)

y = a(x- -3)^2 -1

y = a(x+3)^2 -1

Pick another point  (-2,0) and substitute it into the equation

0 = a(-2+3)^2 -1  to find a

0 =a(1)^2 -1

0 = a-1

1 = a

y = (x+3)^2 -1

Answer Link
amna04352
amna04352 amna04352
  • 09-05-2020

Answer:

y = (x + 3)² - 1

y = x² + 6x + 8

Step-by-step explanation:

Vertex: (-3,-1)

y-intercept: (0,8)

y = a(x - -3)² - 1

y = a(x + 3)² - 1

8 = a(0 + 3)² - 1

9a = 9

a = 1

y = (x + 3)² - 1

y = x² + 6x + 8

Answer Link

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