wishmorethewitch wishmorethewitch

08-05-2020
Mathematics

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cos (theta) = square of 2 / 2, and 3pi/2 < theta < 2pi, evaluate sin (theta) and tan (theta)

cos theta square of 2 2 and 3pi2 lt theta lt 2pi evaluate sin theta and tan theta class=

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juan78940 juan78940

18-05-2020

Answer: negative square root of two over 2 and tan theta is -1

Step-by-step explanation:

Did it on edge and got it right

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