Answer:
x = 4
Step-by-step explanation:
[tex]2log_9(x)=log_98+log_9(x-2) \\ log_9( {x}^{2} )=log_9 \{8 \times (x-2) \} \\ {x}^{2} =8 \times (x-2) \\ {x}^{2} = 8x - 16 \\ {x}^{2} - 8x + 16 = 0 \\ (x - 4)^{2} = 0 \\ x - 4 = 0 \\ \huge \red { \boxed{x = 4}}[/tex]
