sukunshrestha
sukunshrestha sukunshrestha
  • 09-05-2020
  • Mathematics
contestada

Can anyone prove this


4cosec2A ×cot 2A = cosec²A-sec²A

​

Respuesta :

devishri1977
devishri1977 devishri1977
  • 09-05-2020

Answer:

Step-by-step explanation:

[tex]4cosec 2A * cot 2A=\frac{4}{sin 2A}*\frac{cos 2A}{sin 2A}\\\\=\frac{4*(cos^{2}A-sin^{2}A)}{2sinA cosA*2sinAcosA}\\\\=\frac{4*(cos^{2}A-sin^{2}A)}{4sin^{2}Acos^{2}A}\\\\=\frac{cos^{2}A-sin^{2}A}{sin^{2}Acos^{2}A}\\\\=\frac{cos^{2}A}{{sin^{2}Acos^{2}A}}-\frac{sin^{2}A}{sin^{2}Acos^{2}A}\\\\=\frac{1}{sin^{2}A}-\frac{1}{cos^{2}A}\\\\=cosec^{2}A-sec^{2}A[/tex]

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