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10-05-2020
Chemistry

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what is the PH of a 0.05M solution of the strong base Ca(OH)2 at 25C

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drpelezo drpelezo

11-05-2020

Answer:

pH = 14 - pH = 14 - 1 = 13

Explanation:

0.05M Ca(OH)₂ => 0.05M Ca⁺(aq) + 2(0.05M) OH⁻(aq)

pOH = -log[OH⁻] = -log(0.100) = 1

pH = 14 - pH = 14 - 1 = 13

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