Answer:
[tex]=6a-14[/tex]
Step-by-step explanation:
[tex]3\left(4a-3\right)-\left(6a+5\right)\\\mathrm{Expand}\:3\left(4a-3\right):\quad 12a-9\\\mathrm{Apply\:the\:distributive\:law}:\quad \:a\left(b-c\right)=ab-ac\\\mathrm{Simplify}\:3\cdot \:4a-3\cdot \:3:\quad 12a-9\\=12a-9\\-\left(6a+5\right):\quad -6a-5\\=12a-9-6a-5\\\mathrm{Simplify}\:12a-9-6a-5:\quad 6a-14\\=6a-14[/tex]
