padronvaleria1428 padronvaleria1428
  • 10-06-2020
  • Mathematics
contestada

Who much time would it take for a train accelerating at 21.5 m/s2 to go from
13.2 m/s to 38.9 m/s?

Respuesta :

surjithayer10 surjithayer10
  • 10-06-2020

Answer:

Step-by-step explanation:

v=u+at

38.9=13.2+21.5 t

21.5 t=38.9-13.2

21.5 t=25.7

t=25.7/21.5≈1.195 s

Answer Link
gilbertazavedo72
gilbertazavedo72 gilbertazavedo72
  • 10-06-2020

Answer:

To find the time taken, we use the equation:

v

=Then to find the time taken, we use the equation:

v = u + at

where:

v is the final velocity of the train

u is the initial velocity of the train

a is the train's acceleration

t is the time taken

So, we get:

t = (v-u)/a

t = (38.9 - 13.2)/21.5

t = 25.7/21.5

t = 1.19 seconds

Answer Link

Otras preguntas

what is a flower part that elevates the stigma
Which of these would be the BEST topic for a narrative essay? A. my interpretation of the life story of Thomas Jefferson B. what happened when I first saw th
six times a number is two hundred and forty what is The number
Dustin makes $2,330 each month and pays $840 for rent. To the nearest tenth of a percent, what percent of Dustin's earnings are spent on rent? A. 84.0% B. 63.9%
The sides of the DNA molecule, the rails of the ladder, are composed of A. phosphates only. B. nitrogenous bases only. C. phosphates and sugars. D. nitrogenous
In plant cells, differentiation begins _____.
should cheerleading be banned. give reasons please
what is 50000x700? and 100x123,478
what is the answer when you simplify b8 b4
describe the difference between prokaryotic and eukaryotic cells and identify their parts