matosashley45
matosashley45 matosashley45
  • 08-07-2020
  • Mathematics
contestada

Find the area of a rectangle whose side lengths are 4x² and 6x²– 3x.
A. 24x⁶– 12x²
B. 24x⁴ - 3x
C. 24x⁴ - 12x³
D. 20x³- 6x²​

Respuesta :

senalfernando111
senalfernando111 senalfernando111
  • 08-07-2020

Answer:

c

Step-by-step explanation:

4x^2(6x^2-3x)

=24x^4-12x^3

Answer Link
vgonzalezo vgonzalezo
  • 08-07-2020

Answer: C. 24x⁴ - 12x³

Step-by-step explanation:

The area of a rectangle is length × width.

4x² × (6x²– 3x) to answer this, we multiply 4x² for each term inside the parentheses.

4x² × 6x² = 24x⁴    (4 × 6 = 24 and x² × x² = x⁴)

4x² × -3x = -12x³    (4 × -3 = -12 and x² × x = x³)

So the answer is 24x⁴ - 12x³

Answer Link

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