Answer:
[tex]Q=2582J=2.58kJ[/tex]
Explanation:
Hello,
In this case, for us to compute the absorbed heat, we apply the following equation:
[tex]Q=m_{Al}Cp_{Al}(T_2-T_1)[/tex]
Whereas we use the mass, specific heat and temperature change for the piece of aluminium, thus, we obtain:
[tex]Q=63.1g*0.930\frac{J}{g*\°C}*(67.0-23.0)\°C\\ \\Q=2582J=2.58kJ[/tex]
It is positive as the heat is entering, therefore the temperature raises.
Best regards.
