mgiu0avbrown
mgiu0avbrown mgiu0avbrown
  • 06-09-2016
  • Mathematics
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solve a=2pir^2 2pirh for pi

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gibrancn
gibrancn gibrancn
  • 06-09-2016
a = 2[tex] \pi [/tex] [tex] r^{2} [/tex] 2[tex] \pi [/tex]rh   |Divide by 4h[tex] r^{3} [/tex]

[tex] \pi ^{2} [/tex] = [tex] \frac{a}{4h r^{3} } [/tex]          |Square root on both sides

[tex] \pi [/tex] = [tex] \sqrt{ \frac{a}{4h r^{3} } } [/tex]

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