ashisacrustyrat
ashisacrustyrat ashisacrustyrat
  • 06-08-2020
  • Mathematics
contestada

how many 4 digit numbers can be formed if repetitions are not allowed and the numbers always end with 3?
- 405
- 450
- 540
- 504

Respuesta :

CSMedrano
CSMedrano CSMedrano
  • 06-08-2020

Answer:

448

Step-by-step explanation:

we have four spaces

_ _ _ _ but we know that they end in 3

_ _ _ 3 so the question changes how many 3 digit numbers can be formed without repetion and 3

so the first one has 8 options 1,2,4,5,6,7,8,9 we can have 0 here.

the second one 8 we count 0

the third 7 so we have

8*8*7*1=448

dont know why it doesn't fit.

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