jamieanomie
contestada

a uniform metre rule of mass 120g is pivoted at the 60cm mark. at what point on the meter rule showuld a masss of 50g be suspended for it to balance horizontally?

Respuesta :

Zaina190

Answer:

Hey mate! Your ans is 50g

Explanation:

the 120 g mass acts at the center of the metre rule (50 cm mark)

... 10 cm from the pivot

the 50 g mass needs to be on the other side of the pivot (> 60 cm mark)

120 g * 10 cm = 50 g

Hope it helped if yes mark me BRAINLIEST..

Tysm!

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