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  • 09-08-2020
  • Chemistry
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An unknown gas diffuses 5 times slower than that of H2.The moleculer mass of unknown gas is??

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oscar236
oscar236 oscar236
  • 09-08-2020

Answer:

50.

Explanation:

We can write Graham's Law of Diffusion as:

(Rate 1)^2 = Molecular Mass 2

--------------    -------------------------

(Rate 2)^2    Molecular Mass 1

So using the Given Information:

1^2  / (1/5)^2 = Molecular Mass of unknown gas / 2, so:

25 = M/2

M = 50.

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