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06-09-2020
Mathematics

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Find a so that the point (-1,1) is on the graph of f(x)=ax2 +2

Respuesta :

nada2135 nada2135

06-09-2020

Answer:

Step-by-step explanation:

f(x)=ax^2+4

2 = a(-1)^2+4

-2=a(-1)^2

-2/a=(-1)^2

-2/a=1

a=-2

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