trishavidyanand
trishavidyanand trishavidyanand
  • 08-09-2020
  • Chemistry
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[2 Marks] What is the pressure in atm of 16.7 mol helium that occupies a volume of 7.2 L at a temperature of 279 K?

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kinsondols186
kinsondols186 kinsondols186
  • 10-09-2020

Answer:

53.13atm

Explanation:

PV=nRT

P=nRT/V

= 16.7mol*0.0821LatmK^-1mol^-1*279K/7.2L

=53.13atm

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