Answer:
210 gaL 60 % Antifreeze II
Step-by-step explanation:
In the problem, there are two types of antifreeze
antifreeze I and
antifreeze II
antifreeeze I 20 ----70 gal
Antifreeze II 60 ----- x gal
Total 50 ---------------- (70 + x ) gal
20*70+60*x=50(70+x)
1400+60x=3500+50x
60x-50x=3500-1400
10x=2100
x= 210
x=210 gaL 60 % Antifreeze II
