nailealedesma1234 nailealedesma1234
  • 06-10-2020
  • Mathematics
contestada

F(x) = -2x^2 + 6x-3, opens (down or up) and has a (maximum or minimum) value

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ronda5450
ronda5450 ronda5450
  • 06-10-2020

Answer: D

Step-by-step explanation:

(Using the formula in my attachment)

x^2 − 6x + 19

(x - 3)^2 = x^2 - 6x + 9

9 - e = 19

e = -10

(x - 3)^2 - e

(x - 3)^2 - - 10

(x - 3)^2 + 10

when x - 3 = 0, x = 3

Subsitute 3 into the equation

(3 - 3)^2 + 10

0 + 10

Minimum (3,10) in this case f(3) = 10

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