shanny02 shanny02

08-10-2020
Mathematics

contestada

how do you solve y=x²+1

plsss help! show solution!

Respuesta :

genkainokoeru genkainokoeru

08-10-2020

Answer:

[tex]\sqrt{x-1} , -\sqrt{x-1}[/tex]

Step-by-step explanation:

(y=x^2+1)^-1=

x=y^2+1

x-1=y^2

+ or -sqrt(x-1)=y

therefore, y=

[tex]\sqrt{x-1} , -\sqrt{x-1}[/tex]

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