Answer:
Equal the gradient of the given points & of some arbitrary point
Step-by-step explanation:
The gradient of the line = [tex]\frac{6-4}{2-(-2)}=\frac{2}{4} =\frac{1}{2}[/tex]
Select some arbitrary point [tex]p(x,y)[/tex] on that line and rewrite the relationship for the gradient with either point (given) and then equal it to what we just calculated.
[tex]\begin{aligned}\frac{y-6}{x-2} &= \frac{1}{2}\\y-6&= \frac{1}{2}(x-2)\\y&= \frac{1}{2}x+5\end{aligned}[/tex]
