The answer is [tex]k[/tex] ≥ [tex]\frac{91}{12}[/tex]
First, you must flip the equation
[tex]12k+29[/tex] ≥ [tex]120[/tex]
Then, you must subtract 29 on both sides
[tex]12k[/tex] ≥ [tex]91[/tex]
Finally, divide both sides by 12
[tex]k[/tex] ≥ [tex]\frac{91}{12}[/tex]
