Answer:
The coefficient of kinetic friction is .0204081633 and the firction acting upon the object is 1 N
Explanation:
To figure this out I started off with Newton's Second Law F= ma.
(11-x)=5*2. *x is the amount of force that kinetic friction applies on the object
x=1 N
Since F=1 and Friction=Normal-Force*Coifficient-Of-Friction
1=5g(mu)
mu=.0204081633
Hope this helps
