Answer: 0.025 moles of nitrogen gas are there in the sample.
Explanation:
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = 1.03 atm
V = Volume of gas = 568 ml = 0.568 L (1L=1000ml)
n = number of moles = ?
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]279K[/tex]
[tex]n=\frac{PV}{RT}[/tex]
[tex]n=\frac{1.03atm\times 0.568L}{0.0821L atm/K mol\times 279K}=0.025moles[/tex]
0.025 moles of nitrogen gas are there in the sample.
