Calculate the mass of KI in grams required to prepare 9.00 ✕ 102 mL of a 1.40 M solution

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07-10-2016
Chemistry

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Calculate the mass of KI in grams required to prepare 9.00 ✕ 102 mL of a 1.40 M solution

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Willchemistry Willchemistry · Answer 1 · 2016-10-07T20:39:15+02:00

Willchemistry Willchemistry

07-10-2016

Volume in liters:

9.00x10² mL / 1000 => 0.9 L

Molar mass KI => 166.0028 g/mol

Mass KI = volume x molar mass x molarity

Mass KI = 0.9 x 166.0028 x 1.40

= 209.16 g of KI

hope this helps!

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